How safe do YOU feel when walking around town? Apparently, you should feel pretty comfortable.
That’s because Temecula has been dubbed the sixth safest city in America, according to a new report.
The people over at 24/7 Wall Street crunched the numbers provided in the most recent report on violent crimes by the FBI, which are for 2013.
“In addition to crime data, we also reviewed median household income, poverty rates, and educational attainment rates from the 2013 Census Bureau’s American Community Survey,” the authors state.
According to the report, the safest place of all in America is also in Southern California: Irvine. Neighboring Murrieta also scored top marks in the report, coming in at number two
Here’s the information provided on Temecula:
- Violent crimes per 100,000: 85
- Population: 106,680
- Poverty rate: 7.6% (15th lowest)
- Pct. of adults with high school degree: 92.3% (48th highest)
Temecula is situated between Los Angeles and San Diego in the southwestern corner of Riverside County. In 2013, the city of nearly 107,000 residents had just 91 violent crimes in total. Temecula also recorded just 38 aggravated assaults last year, or 36 reported assaults per 100,000 residents. This was lower than in all but two cities. Property crime in Temecula, however, was comparatively more common. Last year, Temecula reported 2,670 such crimes for every 100,000 people, not much lower than the national property crime rate of 2,731 per 100,000.
And here are the top 10 cities in order, as ranked by 24/7 Wall Street:
- Cary, North Carolina
- Naperville, Illinois
- Frisco, Texas
- Gilbert, Arizona
- Amherst, New York